返回首页 >

China’s ‘Double 11’ shopping festival highlights steady consumer demand, longer shopping season

2026-10-15 09:16   环球时报网英文版

  Industry observers said that the annual shopping bonanza has evolved from a one-day frenzy into a month-long consumption campaign, reflecting both platform competition and increasingly rational, fragmented consumer behavior.

  Hu Qimu, a professor at the Maritime Silk Road Institute of Huaqiao University, told the Global Times on Monday that the shift from a one-day shopping frenzy to a longer promotional period has not weakened consumer activity. Instead, it may improve conversion rates, reduce pressure on logistics networks and better support the long-term health of the retail and manufacturing sectors.

  "I"m shopping more rationally this year," said a consumer surnamed Liao in Beijing. "I"ve already joined the pre-sale for items I really need, and I"m comparing prices carefully before placing my final order. I"m not buying just because of the festival — I only purchase what I need."

  Analysts said that the changing format of the festival also reflects a broader transformation in Chinese consumption habits, with shoppers increasingly moving away from "stockpiling" toward more need-based purchases.

  "The "festival fever" is not as intense as it was a few years ago," Hu said, citing two reasons. First, the mechanics of the "Double 11" shopping festival have become mature after years of iteration, leaving little room for disruptive innovation; second, consumers are more rational and no longer concentrate purchases so heavily in a short period.

  Observers noted that as "Double 11" enters its 18th year, the shopping gala represents not only changing consumer trends, but also the deep integration of technology and the coordinated upgrading of industries.

  According to analysts, platforms are experimenting with AI-assisted shopping tools, sometimes described as "AI shopping agents," to help users compare products and complete purchases more efficiently.

猜你喜欢

热点新闻

{$loop_num=0}